8w^2+22w-4=2

Solution for 8w^2+22w-4=2 equation:

8w^2+22w-4=2

We move all terms to the left:

8w^2+22w-4-(2)=0

We add all the numbers together, and all the variables

8w^2+22w-6=0

a = 8; b = 22; c = -6;
Δ = b2-4ac
Δ = 222-4·8·(-6)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-26}{2*8}=\frac{-48}{16}
=-3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+26}{2*8}=\frac{4}{16}
=1/4
$